2.7 Kg of each of water and acetic acid are mixed, The freezing point of the solution will be –x °C.
Summary
The video presents a detailed calculation method for determining the freezing point of a solution containing water and acetic acid. Key concepts covered include the non-dissociating nature of water and acetic acid, molar masses, and the impact of the higher amount of water on solvent behavior. Through various calculations involving molarity and mol values, the new freezing point of the solution is accurately derived, showcasing the practical application of depression freezing point phenomenon in chemistry.
Solution Preparation
The solution is prepared by mixing 2.7 kg of water and acetic acid. The freezing point of the solution is determined to be -x degrees Celsius. It is noted that water is not dissociating acetic acid and not disassociating.
Given Values
The values of nearest integers and molar masses of water and acetic acid are provided. The freezing points of water in Kelvin and acetic acid are also mentioned.
Conversion to Grams
The conversion of mol of water to grams is discussed, resulting in a value of 18 grams/mol of water. The discussion also includes the value of 2.7 in 1000 and the mol of h2o.
Solvent Properties
The higher amount of H2O affects the behavior of the solvent. Water as a solvent leads to basic depression freezing point application.
Solvent Equation
The equation related to the solvent with values of water and molarity is discussed. The mol of water and acetic acid are provided for consideration.
New Freezing Point Calculation
The calculation for the new freezing point is carried out by determining the value for water. Various calculations involving values and units are explained.
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